Joules to Volts Calculator
Convert joules to volts using charge in coulombs (V = J/Q). Calculate voltage from electrical energy for capacitor analysis, battery chemistry, and physics problems.
Voltage
0.0139 V
Voltage (V)
0.0139
Formula Used
V = J / Q = 100 / 7200.0000
V = J / Q (Q = A × seconds)
About the Joules to Volts Calculator
A joules to volts calculator converts electrical energy in joules to voltage using the charge-based relationship V = J/Q — the fundamental definition of electric potential as energy per unit charge. This calculation appears in capacitor circuit analysis (finding the voltage at which a capacitor stores a given energy), battery chemistry (relating energy content to terminal voltage), particle physics (converting particle energy in eV/MeV/GeV to equivalent voltage), and any problem involving the transfer of electrical energy to or from a charge carrier. The volt is literally defined as one joule per coulomb: one volt of potential difference does one joule of work on every coulomb of charge that moves through it. Our calculator accepts joules and charge (in coulombs, or derivable from current and time), and outputs voltage along with equivalent electronvolts and practical kWh context. Used by physics students, electronic engineers designing capacitor discharge circuits, battery system designers, and researchers working with particle accelerators or radiation sources.
Formula
V = J / Q | Q = I × t (seconds) | E_cap = ½CV² → V = √(2E/C) | 1 eV = 1.602×10⁻¹⁹ J
How It Works
V = J / Q, where Q is charge in coulombs. For a circuit with known current and time: Q = I × t (amperes × seconds). Example 1 (battery): 12V, 60Ah car battery. Total energy: E = V × Q = 12 × (60 × 3,600) = 12 × 216,000 = 2,592,000J. Reverse: if you know energy (2,592,000J) and charge (216,000C), V = 2,592,000 / 216,000 = 12V. Example 2 (capacitor charging): if a 1,000μF capacitor stores 500mJ: Using E = ½CV²: V = √(2E/C) = √(2 × 0.5 / 0.001) = √1,000 = 31.6V. Verification: Q = CV = 0.001 × 31.6 = 0.0316C. J = V × Q = 31.6 × 0.0316 = 0.999J ≈ 1J ✓. Example 3 (particle physics): an alpha particle carrying 2 elementary charges (2 × 1.602×10⁻¹⁹C) gaining 9.6×10⁻¹⁹J of kinetic energy: V = 9.6×10⁻¹⁹ / (2 × 1.602×10⁻¹⁹) = 9.6 / 3.204 = 3V equivalent accelerating voltage.
Tips & Best Practices
- ✓Supercapacitor energy storage: a 100F supercapacitor (ultracapacitor) charged to 2.7V stores E = ½ × 100 × 2.7² = 364.5J. Converting back: V = J/Q is consistent. These devices store 10-100× more energy than conventional electrolytic capacitors at low voltage — ideal for hybrid vehicles and grid energy buffering.
- ✓Implantable defibrillator (ICD): delivers approximately 25-40J per therapeutic shock. Charged to 700-900V: Q = J/V = 40/800 = 0.05C = 50 mC. Capacitor used: C = Q/V = 0.05/800 = 62.5μF. This micro-scale energy delivery at high voltage requires precisely designed capacitors and discharge circuits.
- ✓Nuclear radiation measurement: 1 Gray (Gy) of radiation dose = 1 J/kg of tissue. For tissue with charge carrier density: converting Gray to equivalent voltage is complex, but the J to V path through charge provides a bridge for medical physics calculations.
Who Uses This Calculator
Electronics engineers designing capacitor discharge circuits who need to find operating voltage from stored energy. Physics students solving problems relating electric potential to energy and charge. Battery engineers characterizing cell voltage from measured energy capacity and charge throughput. Particle physicists converting particle beam energies between electronvolts and equivalent accelerating voltages.
Optimised for: USA · UK · Canada · Australia · Calculations run in your browser · No data stored
Frequently Asked Questions
How do I convert joules to volts?
V = J / Q, where Q is charge in coulombs. For a circuit: Q = A × seconds. Example: 240J with 2A flowing for 10 seconds: Q = 20C; V = 240 / 20 = 12V.
How is voltage related to energy in physics?
Voltage (electric potential) is energy per unit charge: 1V = 1J/C. This means 1 joule of work is done moving 1 coulomb of charge through a 1 volt potential difference. This relationship is fundamental to capacitor and battery chemistry.
What voltage does a capacitor need to store 1 joule?
Capacitor energy: E = ½CV². For a 1F supercapacitor to store 1J: 1 = ½ × 1 × V²; V = √2 = 1.414V. For a 0.001F (1mF) capacitor: V = √(2/0.001) = 44.7V. Smaller capacitors need much higher voltage to store the same energy.